(0.0625x^2)+(0.25x)+1=0

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Solution for (0.0625x^2)+(0.25x)+1=0 equation:


Simplifying
(0.0625x2) + (0.25x) + 1 = 0

Reorder the terms:
1 + (0.25x) + (0.0625x2) = 0

Solving
1 + (0.25x) + (0.0625x2) = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
0.0625 the coefficient of the squared term: 

Divide each side by '0.0625'.
16 + (4x) + x2 = 0

Move the constant term to the right:

Add '-16' to each side of the equation.
16 + (4x) + -16 + x2 = 0 + -16

Reorder the terms:
16 + -16 + (4x) + x2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + (4x) + x2 = 0 + -16
(4x) + x2 = 0 + -16

Combine like terms: 0 + -16 = -16
(4x) + x2 = -16

The x term is (4x).  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
(4x) + 4 + x2 = -16 + 4

Reorder the terms:
4 + (4x) + x2 = -16 + 4

Combine like terms: -16 + 4 = -12
4 + (4x) + x2 = -12

Factor a perfect square on the left side:
((x) + 2)((x) + 2) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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